Mathematics for IGCSE & O level - Proportion (Section 1 - No. 26)
Given that *y* varies inversely as *x*2, and *y* = 4 when *x* = 1.5, what is the value of *y* when *x* = 3?
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ব্যাখ্যা
y = k/x^2. Substitute values to get 4 = k/1.5^2. Then k=9. Therefore, y = 9/3^2 = 1.